A suspension bridge will therefore have a cable and a stiffening girder. Bending moment and shears will be absent if the arch is parabolic and the loading uniformly distributed.Ī cable can take only tension. The arch will be under pure compression that will be economical.ĭifference between the basic action of an arch and a suspension cableĪn arch is essentially a compression member, which can also take bending moments and shears. Hence, the bending moment at every section of the arch will be zero. Hence the intercept between the theoretical arch and actual arch is zero everywhere. Because, both, the shape of the arch and the shape of the bending moment diagram are parabolic. Parabolic arches are preferable to carry distributed loads. The normal thrust and radial shear in an arch rib. if H is the horizontal thrust and V the net vertical shear at X, from theb free body of the RHS of the arch, it is clear that V and H will have normal and radial components given by, Let ?be the inclination of the tangent at X. Calculate the resultant at the end hinges. it carries a udl of 30 kN/m run over the left hand half of the span. 1.A three hinged parabolic arch hinged at the crown and springing has a horizontal span of 12m and a central rise of 2.5m.
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